你的回合会交给对手多少

Only the last play of your turn. You keep playing while the counter is on your side, and the moment it crosses, the turn passes and whatever it crossed by is what they get.

The total you spent does not appear anywhere in that. Four cheap plays that land you one past zero hand over one; a single expensive play that lands you six past zero hands over six.

It changes both of the things you care about, and usually not in the same direction. Cheapest first always fits the most plays into a turn, and it very often gives away more than you needed to.

With seven on the counter and plays costing one, two, three and four, cheapest first gets all four down and hands over three. Giving up one play brings the handover down to one.

It is the right habit for squeezing plays out of a turn, and that was checked rather than assumed: across twenty thousand random hands it never lost to any other order on the number of plays.

It is not the right habit for keeping the handover small, and it lost on that in about four hands out of ten. Which of the two you want is the part of the decision the arithmetic cannot make for you.

That every play on your list is legal when its turn comes, that costs are fixed, and that nothing gives the counter back to you part way through the turn.

Anything that moves the counter the other way, or that changes what a play costs once the turn has started, sits outside it.